i(z^2)+2z-1-i=0

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Solution for i(z^2)+2z-1-i=0 equation:


Simplifying
i(z2) + 2z + -1 + -1i = 0

Multiply i * z2
iz2 + 2z + -1 + -1i = 0

Reorder the terms:
-1 + -1i + iz2 + 2z = 0

Solving
-1 + -1i + iz2 + 2z = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + -1i + iz2 + 1 + 2z = 0 + 1

Reorder the terms:
-1 + 1 + -1i + iz2 + 2z = 0 + 1

Combine like terms: -1 + 1 = 0
0 + -1i + iz2 + 2z = 0 + 1
-1i + iz2 + 2z = 0 + 1

Combine like terms: 0 + 1 = 1
-1i + iz2 + 2z = 1

Add '-2z' to each side of the equation.
-1i + iz2 + 2z + -2z = 1 + -2z

Combine like terms: 2z + -2z = 0
-1i + iz2 + 0 = 1 + -2z
-1i + iz2 = 1 + -2z

Reorder the terms:
-1 + -1i + iz2 + 2z = 1 + -2z + -1 + 2z

Reorder the terms:
-1 + -1i + iz2 + 2z = 1 + -1 + -2z + 2z

Combine like terms: 1 + -1 = 0
-1 + -1i + iz2 + 2z = 0 + -2z + 2z
-1 + -1i + iz2 + 2z = -2z + 2z

Combine like terms: -2z + 2z = 0
-1 + -1i + iz2 + 2z = 0

The solution to this equation could not be determined.

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